Quick Answer
Drawing one ace from a standard 52-card deck has probability 4/52 = 0.0769, or about 7.69%, with odds of 4:48 (simplified 1:12).
Single Event Probability
Combined Independent Events
Conditional Probability P(A|B)
Common Examples
| Input | Result |
|---|---|
| 4 favorable out of 52 total | P = 0.0769 (7.69%), odds 1:12 |
| P(A) = 0.5, P(B) = 0.5 (AND) | P(A and B) = 0.25 (25%) |
| P(A) = 0.5, P(B) = 0.5 (OR) | P(A or B) = 0.75 (75%) |
| P(A and B) = 0.12, P(B) = 0.4 | P(A|B) = 0.3 (30%) |
| 1 favorable out of 6 total | P = 0.1667 (16.67%), odds 1:5 |
How It Works
Single Event Probability
The probability of a single event is the ratio of favorable outcomes to total possible outcomes:
P(E) = favorable outcomes / total outcomes
This value always falls between 0 and 1. A probability of 0 means the event is impossible; a probability of 1 means it is certain.
The complement of an event is the probability it does NOT occur: P(not E) = 1 - P(E).
Odds express probability as a ratio of favorable to unfavorable outcomes. If P(E) = 1/6, the odds in favor are 1:5 (one favorable outcome for every five unfavorable).
Combined Independent Events
Two events are independent if the occurrence of one does not affect the probability of the other (such as two separate coin flips).
AND (intersection): P(A and B) = P(A) * P(B). The probability that all events occur is the product of their individual probabilities.
OR (union): P(A or B) = 1 - (1 - P(A)) * (1 - P(B)). For independent events, the probability that at least one occurs equals one minus the probability that none occur.
Conditional Probability
| **P(A | B)** is the probability of event A given that event B has already occurred: |
| **P(A | B) = P(A and B) / P(B)** |
This formula requires P(B) > 0. Conditional probability is the foundation of Bayes’ theorem and is central to statistics, machine learning, and decision-making.
Worked Example
A standard deck has 52 cards. The probability of drawing an ace is P = 4/52 = 1/13 = 0.0769 (about 7.69%). The complement is 1 - 0.0769 = 0.9231. The odds of drawing an ace are 4:48, which simplifies to 1:12.
For two independent coin flips (each P = 0.5): P(both heads) = 0.5 * 0.5 = 0.25. P(at least one head) = 1 - (0.5)(0.5) = 0.75.
| For conditional probability: if 12% of customers buy both product A and B, and 40% buy product B, then P(A | B) = 0.12 / 0.40 = 0.30, meaning 30% of product B buyers also buy product A. |
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