Quick Answer
A 12-ohm resistor with 2 amps of current flowing through it has a voltage drop of 24.00 V and dissipates 48.00 W of power.
Ohm's Law (V = IR)
Electrical Power (P = VI)
Common Examples
| Input | Result |
|---|---|
| I = 2 A, R = 12 ohms | V = 24.00 V |
| V = 120 V, R = 60 ohms | I = 2.00 A |
| V = 9 V, I = 0.5 A | R = 18.00 ohms |
| V = 120 V, I = 10 A | P = 1,200.00 W |
| V = 5 V, I = 0.02 A | P = 0.10 W |
How It Works
This calculator uses two fundamental electrical formulas.
Ohm’s Law
V = I x R
Where:
- V = voltage in volts (V), the electrical potential difference
- I = current in amperes/amps (A), the flow of electric charge
- R = resistance in ohms (the Greek letter omega), the opposition to current flow
Rearranged forms:
- Voltage: V = I x R
- Current: I = V / R
- Resistance: R = V / I
Electrical Power
P = V x I
Where P is power in watts (W). Power can also be expressed using Ohm’s Law substitutions:
- P = I^2 x R (substituting V = IR)
- P = V^2 / R (substituting I = V/R)
Understanding the Relationships
Voltage is the “pressure” that pushes electrical current through a circuit. Resistance opposes that flow. Higher resistance means less current for the same voltage. Power measures the rate of energy transfer or consumption.
Common Values
- Standard US household outlet: 120 V
- Standard European household outlet: 230 V
- USB port: 5 V
- Car battery: 12 V
- AA battery: 1.5 V
Worked Example
A 60-watt light bulb operates on a 120 V circuit. The current drawn is I = P / V = 60 / 120 = 0.50 A. The resistance of the filament is R = V / I = 120 / 0.50 = 240 ohms. Alternatively, using Ohm’s Law: if a 12-ohm resistor carries 2 A of current, the voltage across it is V = 2 x 12 = 24 V, and the power dissipated is P = 24 x 2 = 48 W.
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