Quick Answer
0.5 moles of solute dissolved in 1.0 L of solution gives a molarity of 0.5000 M. Dissolving 58.44 g of NaCl (molar mass 58.44 g/mol) in 1 L yields a 1.0000 M solution.
Molarity (M = mol / L)
Mass and Volume to Molarity
Common Examples
| Input | Result |
|---|---|
| 0.5 mol in 1.0 L | M = 0.5000 M |
| M = 2.0 M, V = 0.25 L | Moles = 0.5000 mol |
| 0.1 mol, M = 0.5 M | V = 0.2000 L (200 mL) |
| 58.44 g NaCl, molar mass 58.44 g/mol, 1 L | Molarity = 1.0000 M |
| 40 g NaOH, molar mass 40 g/mol, 0.5 L | Molarity = 2.0000 M |
How It Works
The Molarity Formula
M = n / V
Where:
- M = molarity in moles per liter (mol/L or M)
- n = moles of solute (mol)
- V = volume of solution in liters (L)
Rearranged:
- Moles: n = M x V
- Volume: V = n / M
From Mass to Molarity
When starting with a known mass of solute rather than moles:
M = (mass / molar mass) / V
First convert grams to moles by dividing by the molar mass, then divide by the volume in liters.
Molarity vs. Molality
Molarity (M) is moles of solute per liter of solution. Molality (m) is moles of solute per kilogram of solvent. Molarity changes with temperature because liquid volumes expand and contract. Molality does not change with temperature because mass is independent of temperature. For dilute aqueous solutions at room temperature, the values are nearly identical.
Common Molarities in the Lab
- Concentrated HCl: approximately 12 M
- Concentrated H2SO4: approximately 18 M
- Concentrated NaOH: approximately 19 M
- Saturated NaCl: approximately 6.1 M
- Typical lab dilute acid: 0.1 to 1.0 M
Worked Example
Dissolve 4.0 grams of NaOH (molar mass = 40.00 g/mol) in enough water to make 500 mL (0.5 L) of solution. Moles = 4.0 / 40.00 = 0.10 mol. Molarity = 0.10 / 0.5 = 0.20 M. The resulting solution is 0.20 M NaOH. To find how many moles are in 250 mL of this solution: n = 0.20 x 0.25 = 0.05 mol.
CalculateY