Quick Answer
A 10 kg object moving at 5 m/s has a kinetic energy of 0.5 x 10 x 25 = 125 J. A 1,500 kg car traveling at 20 m/s (about 45 mph) has a kinetic energy of 300,000 J (300 kJ).
Common Examples
| Input | Result |
|---|---|
| m = 10 kg, v = 5 m/s | KE = 125.00 J |
| m = 1,500 kg, v = 20 m/s | KE = 300,000.00 J |
| KE = 500 J, v = 10 m/s | m = 10.00 kg |
| KE = 200 J, m = 4 kg | v = 10.00 m/s |
| m = 0.145 kg, v = 40 m/s | KE = 116.00 J |
How It Works
The Formula
The kinetic energy formula describes the energy of a moving object:
KE = ½ x m x v²
Where:
- KE = kinetic energy in joules (J)
- m = mass of the object in kilograms (kg)
- v = velocity (speed) of the object in meters per second (m/s)
This equation can be rearranged to solve for any of the three variables:
- Kinetic energy: KE = 0.5 x m x v²
- Mass: m = 2 x KE / v²
- Velocity: v = sqrt(2 x KE / m)
Key Properties of Kinetic Energy
Kinetic energy depends on the square of velocity, which means doubling the speed quadruples the kinetic energy. This is why highway speed collisions are far more destructive than low-speed impacts. A car going 60 mph has four times the kinetic energy of the same car going 30 mph.
Kinetic energy is always zero or positive. An object at rest (v = 0) has zero kinetic energy. Mass is always positive, and squaring the velocity eliminates any directional sign.
Units
In SI units, mass is in kilograms and velocity is in meters per second, giving kinetic energy in joules (J). One joule equals one kilogram-meter-squared per second-squared (kg x m² / s²).
Relationship to Work
The work-energy theorem states that the net work done on an object equals the change in its kinetic energy: W = ΔKE. This means the energy required to accelerate an object from rest to a given speed equals its kinetic energy at that speed.
Worked Example
For a 10 kg object moving at 5 m/s: KE = 0.5 x 10 x 5² = 0.5 x 10 x 25 = 125 J. To find the mass of an object with KE = 500 J and v = 10 m/s: m = 2 x 500 / 10² = 1,000 / 100 = 10 kg. To find the velocity of a 4 kg object with KE = 200 J: v = sqrt(2 x 200 / 4) = sqrt(100) = 10 m/s. For a baseball (0.145 kg) thrown at 40 m/s (about 90 mph): KE = 0.5 x 0.145 x 40² = 0.5 x 0.145 x 1,600 = 116 J.
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