Quick Answer
100 grams of a substance with a half-life of 5 years has 25.00 grams remaining after 10 years (two half-lives elapsed, 75.00 grams decayed).
Calculate Remaining Quantity
Any time unit (years, hours, seconds, etc.)
Same time unit as half-life
Find Half-Life from Decay Data
Common Examples
| Input | Result |
|---|---|
| N0 = 100 g, t_half = 5 years, t = 10 years | Remaining: 25.00 g (25.00%) |
| N0 = 500 g, t_half = 8 hours, t = 24 hours | Remaining: 62.50 g (12.50%) |
| N0 = 200 g, t_half = 30 days, t = 90 days | Remaining: 25.00 g (12.50%) |
| N0 = 1000 g, N = 250 g, t = 10 years | Half-life: 5.00 years |
| N0 = 400 g, N = 100 g, t = 6 hours | Half-life: 3.00 hours |
How It Works
The Decay Formula
N(t) = N₀ x (1/2)^(t / t_half)
Where:
- N(t) = quantity remaining at time t
- N₀ = initial quantity at time zero
- t = elapsed time
- t_half = half-life (time for half the substance to decay)
After each half-life period, exactly half of the remaining substance has decayed. After 1 half-life, 50% remains. After 2 half-lives, 25%. After 3 half-lives, 12.5%. After 10 half-lives, about 0.1% remains.
Solving for Half-Life
Given measured initial and remaining quantities plus elapsed time:
t_half = t x ln(2) / ln(N₀ / N)
This is derived by taking the natural logarithm of both sides of the decay equation and solving for the half-life.
Decay Constant
The decay constant (lambda) relates to half-life as: lambda = ln(2) / t_half. The decay formula can also be written as N(t) = N₀ x e^(-lambda x t).
Applications
Half-life calculations apply to radioactive decay (nuclear physics), drug metabolism (pharmacology), chemical reaction kinetics, and any process that follows first-order exponential decay. Carbon-14 dating, for example, uses the 5,730-year half-life of C-14 to estimate the age of organic materials.
Notable Half-Lives
- Carbon-14: 5,730 years
- Uranium-238: 4.47 billion years
- Iodine-131: 8.02 days
- Radon-222: 3.82 days
- Caffeine in the body: approximately 5 hours
Worked Example
A lab starts with 500 mg of Iodine-131 (half-life = 8.02 days). After 24.06 days: halvings = 24.06 / 8.02 = 3.00. Remaining = 500 x (0.5)^3 = 500 x 0.125 = 62.50 mg. So 437.50 mg has decayed, and 12.50% remains.
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