Quick Answer
The gravitational force between Earth and the Moon is approximately 1.98 × 10²⁰ N. Two 1 kg masses 1 meter apart experience a force of 6.674 × 10⁻¹¹ N.
Common Examples
| Input | Result |
|---|---|
| m₁ = 5.972×10²⁴ kg (Earth), m₂ = 7.342×10²² kg (Moon), r = 3.844×10⁸ m | F ≈ 1.98×10²⁰ N |
| m₁ = 1 kg, m₂ = 1 kg, r = 1 m | F = 6.674×10⁻¹¹ N |
| m₁ = 5.972×10²⁴ kg (Earth), m₂ = 80 kg (person), r = 6.371×10⁶ m | F ≈ 784.5 N |
| F = 784.5 N, m₁ = 5.972×10²⁴ kg, r = 6.371×10⁶ m | m₂ ≈ 80 kg |
How It Works
Newton’s law of universal gravitation
\[F = \frac{G m_1 m_2}{r^2}\]Where:
- F = gravitational force in Newtons (N)
- G = gravitational constant = 6.674 × 10⁻¹¹ N m²/kg²
- m₁ = mass of the first object in kilograms (kg)
- m₂ = mass of the second object in kilograms (kg)
- r = distance between the centers of the two masses in meters (m)
The gravitational constant G
G = 6.674 × 10⁻¹¹ N m²/kg² is one of the fundamental constants of nature. It was first measured by Henry Cavendish in 1798 using a torsion balance. Its small value explains why gravity between everyday objects is imperceptible — two 1 kg masses 1 meter apart attract each other with a force of only 6.674 × 10⁻¹¹ N, roughly 15 billion times weaker than the weight of a grain of sand.
Rearranged forms
- Force: F = G m₁ m₂ / r²
- Mass 1: m₁ = F r² / (G m₂)
- Mass 2: m₂ = F r² / (G m₁)
- Distance: r = √(G m₁ m₂ / F)
The inverse square law
Gravitational force decreases with the square of the distance. Doubling the distance reduces the force by a factor of four. Tripling the distance reduces it by a factor of nine. This inverse square relationship means gravity weakens rapidly with distance but technically never reaches zero.
Worked example
A 70 kg person stands on Earth’s surface. Earth’s mass is 5.972 × 10²⁴ kg and its radius is 6.371 × 10⁶ m.
F = (6.674 × 10⁻¹¹ × 5.972 × 10²⁴ × 70) / (6.371 × 10⁶)²
F = (2.788 × 10¹⁶) / (4.059 × 10¹³)
F ≈ 687 N
This is the weight of a 70 kg person at Earth’s surface, consistent with W = mg = 70 × 9.81 = 686.7 N.
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