Quick Answer
The cross product of (1, 2, 3) and (4, 5, 6) is (-3, 6, -3) with a magnitude of approximately 7.35.
Vector A
Vector B
Common Examples
| Input | Result |
|---|---|
| (1, 0, 0) x (0, 1, 0) | (0, 0, 1), magnitude 1 |
| (1, 2, 3) x (4, 5, 6) | (-3, 6, -3), magnitude 7.35 |
| (2, 4, 6) x (1, 2, 3) | (0, 0, 0), parallel vectors |
| (3, -1, 2) x (1, 4, -2) | (-6, 8, 13), magnitude 16.16 |
How It Works
The formula
The cross product of two 3D vectors produces a vector perpendicular to both inputs. For vectors \(\mathbf{A} = (a_1, a_2, a_3)\) and \(\mathbf{B} = (b_1, b_2, b_3)\):
\[\mathbf{A} \times \mathbf{B} = (a_2 b_3 - a_3 b_2,\ a_3 b_1 - a_1 b_3,\ a_1 b_2 - a_2 b_1)\]This can also be written as the determinant of a 3x3 matrix with unit vectors i, j, k in the first row.
The magnitude of the cross product equals the area of the parallelogram formed by the two vectors:
\[|\mathbf{A} \times \mathbf{B}| = |\mathbf{A}||\mathbf{B}|\sin\theta\]where \(\theta\) is the angle between the vectors.
Key properties
- The cross product is anticommutative: A x B = -(B x A)
- Parallel vectors have a cross product of zero (sin 0 = 0)
- Perpendicular unit vectors have a cross product magnitude of 1
- The result is always perpendicular to both input vectors (right-hand rule)
Worked example
For A = (1, 2, 3) and B = (4, 5, 6):
- x-component: (2)(6) - (3)(5) = 12 - 15 = -3
- y-component: (3)(4) - (1)(6) = 12 - 6 = 6
- z-component: (1)(5) - (2)(4) = 5 - 8 = -3
Result: (-3, 6, -3). Magnitude = sqrt(9 + 36 + 9) = sqrt(54) = 7.35.
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