Quick Answer
A gas at 2 atm in a 10 L container compressed to 5 L reaches 4 atm. Doubling the volume of a gas at 1 atm drops the pressure to 0.5 atm.
Common Examples
| Input | Result |
|---|---|
| P₁ = 2 atm, V₁ = 10 L, V₂ = 5 L | P₂ = 4 atm |
| P₁ = 1 atm, V₁ = 22.4 L, P₂ = 2 atm | V₂ = 11.2 L |
| V₁ = 5 L, P₂ = 3 atm, V₂ = 10 L | P₁ = 6 atm |
| P₁ = 4 atm, P₂ = 1 atm, V₂ = 20 L | V₁ = 5 L |
| P₁ = 1 atm, V₁ = 1 L, P₂ = 0.5 atm | V₂ = 2 L |
How It Works
Boyle’s Law
P₁V₁ = P₂V₂
Where:
- P₁ = initial pressure (atm)
- V₁ = initial volume (L)
- P₂ = final pressure (atm)
- V₂ = final volume (L)
Temperature must remain constant throughout. This is the key constraint: Boyle’s law applies only to isothermal (constant-temperature) processes.
Rearranged forms:
- Initial Pressure: P₁ = P₂V₂ / V₁
- Initial Volume: V₁ = P₂V₂ / P₁
- Final Pressure: P₂ = P₁V₁ / V₂
- Final Volume: V₂ = P₁V₁ / P₂
Background
Robert Boyle published this relationship in 1662, making it one of the earliest quantitative laws in chemistry. The law describes the inverse relationship between pressure and volume: when you compress a gas (decrease volume), its pressure increases proportionally, and vice versa. Plot pressure against the reciprocal of volume and you get a straight line through the origin.
Boyle’s law is one of the three classical gas laws. Charles’s Law describes the volume-temperature relationship at constant pressure, and Gay-Lussac’s Law describes the pressure-temperature relationship at constant volume. Together with Avogadro’s law, these combine into the ideal gas law: PV = nRT.
Worked example
A bicycle pump contains air at 1 atm and 500 mL. The piston compresses the air to 125 mL. What is the resulting pressure (assuming no air escapes and temperature stays constant)?
P₂ = P₁V₁ / V₂ = (1 atm x 500 mL) / 125 mL = 4 atm
Compressing the air to one quarter of its original volume quadruples the pressure to 4 atm.
Limitations
Boyle’s law applies to ideal gases. Real gases deviate at very high pressures (where molecular volume becomes significant) and near condensation points (where intermolecular attractions matter). For most chemistry and physics problems at standard conditions, the deviation is small enough to ignore.
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